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A baseball popped straight up into the air and had a hang-time of 8.55 s. Determine the height to which the ball rises before it reaches its peak.

Respuesta :

The height which the ball reaches before its peak is 90 m.

Equations of motion

The equations of motion are used to solve problems that have to do with uniformly accelerated motion. We have to use the equation;

v = u - gt to obtain the initial velocity

At maximum height, v = 0 but g = 9.8 ms-2 so;

u = gt

Since equal time is required for going up and coming down, the time for going up is 4.3 seconds

u = 4.3 seconds × 9.8 ms-2 = 42 m/s

Using;

v^2 = u^2 - 2gh

u^2 = 2gh

h = u^2/2g

h = (42 m/s)^2/2 × 9.8 ms-2 = 90 m

The height which the ball reaches before its peak is 90 m.

Learn more about equations of motion:https://brainly.com/question/8898885

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