Question

Find molarity in 1.0 grams of potassium fluoride is dissolved to make 0.10 L of solution.

Answer 1

We are given –

• Weight of $\bf KF$ is = 1g
• Volume, V = 0.10 L

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• Molar Mass of $\bf KF$ –

$\qquad$ $\twoheadrightarrow\bf 39.09 +18.99$

$\qquad$ $\twoheadrightarrow\bf 58.08$

Using formula –

$\qquad$ $\purple{\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ W}{MV}}$

$\qquad$ $\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{ 1}{58.08\times 0.10}$

$\qquad$ $\twoheadrightarrow\bf Molarity _{(Solution)} = \dfrac{1}{5.808}$

$\qquad$ $\purple{\twoheadrightarrow\bf Molarity _{(Solution)} = 0.1722M}$

• Henceforth, Molarity of the solution is = 0.1722M.

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