Answer:
D. The function approaches 1 as x approaches [tex]-\infty[/tex] and [tex]\infty[/tex]
Step-by-step explanation:
When evaluating end behavior, take the limit as the function goes to negative and positive infinity.
When evaluating limits to infinity, terms less than the highest degree are irrelevant:
[tex]\displaystyle \lim_{x\rightarrow \infty}\frac{x^2-4}{x^2-9}=\frac{\infty^2}{\infty^2}=1\\\\\lim_{x\rightarrow -\infty}\frac{x^2-4}{x^2-9}=\frac{(-\infty)^2}{(-\infty)^2}=1[/tex]
Therefore, the function approaches 1 as x approaches [tex]-\infty[/tex] and [tex]\infty[/tex]