From the question it is given that,
Length of the park (L) = 700 m
Breadth of the park (B) = 300 m
Then,
Area of the park = length × breadth
= 700 × 300
= 210000 m2
Let us assume that ABCD is the one cross road and EFGH is another cross road in the park.
The length of ABCD cross road = 700 m
The length of EFGH cross road = 300 m
Both cross road have the same width = 10 m
Then,
Area of the ABCD cross road = length × breadth
= 700 × 10
= 7000 m2
Area of the EFGH cross road = length × breadth
= 300 × 10
= 3000 m2
Area of the IJKL at center = length × breadth
= 10 × 10
= 100 m2
Area of the roads = Area of ABCD + Area of EFGH – Area of IJKL
= 7000 + 3000 – 100
= 10000 – 100
= 9900 m2
We know that, for 1 hectare = 10000 m2
Hence, area of roads in hectare = 9900/10000
= 0.99 hectare
Finally, Area of the park excluding roads = Area of park – Area of the roads
= 210000 – 9900
= 200100 m2
= 200100/10000
= 20.01
Hope that helps! Have a good day :)
