y² + 2y - 15 = 0
y² + 5y - 3y - 15 = 0
y(y + 5) - 3(y + 5) = 0
(y + 5) (y - 3) = 0
taking (y + 5) = 0 => y = -5
now taking (y - 3) = 0 => y = 3
So, the required factors of the given equation are -5 and 3
In this exercise we have to factor the equation given in the statement, so we have to:
The factors of the given equation are -5 and 3.
So from the given equation we have that:
[tex]y^2 + 2y - 15 = 0\\y^2 + 5y - 3y - 15 = 0\\y(y + 5) - 3(y + 5) = 0\\(y + 5) (y - 3) = 0[/tex]
See more about factorise at brainly.com/question/20293447