Answer:
(0, -2) and (1, 0)
Step-by-step explanation:
y = x² + x - 2 and y = 2x - 2
y = x² + x - 2 ⇔ do not change; y = x² + x - 2
y = 2x - 2 ⇔ multiply by -1 ; -y = - 2x + 2
Now add the two equations:
y = x² + x - 2
(+) -y = - 2x + 2
0 = x² - 2x + x + 0
0 = x² - x
0 = x (x - 1) Factor out x
0 = x; 0 = x - 1 Set each factor = to 0 and solve.
x = 0; x = 1
Substitution the value of x into both equations and solve for y
If x = 0 If x = 1
y = (0)² + 0 - 2 ; y = 2(0) - 2 y = 1² + 1 - 2 ; y = 2(1) -2
y = 0 +0 -2 ; y = 0 - 2 y = 1 + 1 -2 ; y = 2 - 2
y = -2 ; y = -2 y = 0 ; y = 0
Solutions to the question: (0, -2) and (1, 0)