Question

The area of a rectangle is 5 x cubed 19 x squared 6 x minus 18 with length x 3. Using synthetic division, what is the width of the rectangle? 5 x squared 4 x minus 6 5 x squared 34 x 108 StartFraction 306 Over x 3 EndFraction 5 x cubed 4 x squared minus 6 x 5 x squared 34 x 108 StartFraction 306 Over x minus 3 EndFraction.

Answer 1

The area of the rectangle is the product of its dimensions.

The width of the rectangle is $5(19x^2 + 6x - 18)$

How to calculate the width of the rectangle

The area of the rectangle is given as:

$Area = 5x^3(19x^2 + 6x - 18)$

The length of the rectangle is given as:

$Length =x^3$

So, we have:

$Area = Length * Width$

Substitute known values

$5x^3(19x^2 + 6x - 18)= x^3* Width$

Divide through by x^3

$5(19x^2 + 6x - 18)= Width$

Rewrite the equation as:

$Width = 5(19x^2 + 6x - 18)$

Hence, the expression that represents the width of the rectangle is $5(19x^2 + 6x - 18)$

Read more about areas at:

https://brainly.com/question/14137384

Answer 2

Answer:

the answer is D

Step-by-step explanation: