Question

A mixture of gas expands from 0.03m³ to 0.06m³ at constant pressure of 1MPa & absorbs energy of 84 J. Calculate the change in internal energy?

Answer 1

Answer:54 kj

Explanation:P1 = P2 = 1000 kPa

1Q2 = 84 kJ

1W2 = P1 (V2 – V1)

= 1000 (0.06 – 0.03) = 30 kJ

1Q2 = 1W2 + 1U2

U2 – U1= 1Q2 – 1W2 = 84 – 30 = 54 kJ