Question

r = 4/3 ( p - q ) solve for p

Answer 1

Answer:

$\huge{\boxed{\sf\:p=\frac{3R}{4}+q}}$

Step-by-step explanation:

Let's use the distributive property at first to remove the brackets.

$\sf\:R = \frac { 4 } { 3 } ( p - q )\\\\\sf\:R=\frac{4}{3}p-\frac{4}{3}q$

Now, let's bring 4/3 p to the left side of the equation & R to the right side.

$\sf\:R=\frac{4}{3}p-\frac{4}{3}q \\\\\sf\frac{4}{3}p=R+\frac{4}{3}q$

Now, to bring the same denominator for all the values, let's divide all the numbers by 4/3. So,

$\sf\:\frac{4}{3}p=R+\frac{4}{3}q \\\\\sf\:\frac{\frac{4}{3}p}{\frac{4}{3}}=\frac{\frac{4q}{3}+R}{\frac{4}{3}}$

We know that, dividing by 4/3 will undo the multiplication by 4/3.

$\sf\:p=\frac{\frac{4q}{3}+R}{\frac{4}{3}}$

And by further dividing, we'll get our answer as,

$\large{\boxed{\sf\:p=\frac{3R}{4}+q }}$

_________

Hope it helps!

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$\mathfrak{Lucazz}$

Answer 2

Answer:

$Given,r = \frac{4}{3} (p - q)$

• Multiply both sides by 3:

$= r \times 3 = \frac{4}{ \cancel3} (p - q) \times \cancel 3$

$= 3r = 4(p - q)$

• Divide both sides by 4:

$= \frac{3r}{4} = \frac{ \cancel4(p - q)}{ \cancel4}$

$= p - q = \frac{3r}{4}$

• Add q to the both sides:

$= p - q + q = \frac{3r}{4} + q$

$=p = \frac{3r}{4} + q$