By conservation of momentum, we will see that the initial velocity of the torpedo is 15.4 m/s
The conservation of momentum says that the total momentum before the collision must be the same as after the collision.
Before the collision we have a momentum:
P₀ = torpedo momentum + target momentum.
Where the momentum is given by:
Momentum = Mass×Velocity.
Then the initial momentum is:
P₀ = (1450kg)*V + (670 kg)*0m/s
Where V is the initial velocity of the torpedo.
For the final momentum, the torpedo and the target travel together with a velocity of 10.6 m/s, so we can see that the final momentum is:
P₁ = (1450kg + 670kg)*10.6m/s
Because of the conservation, we must have:
P₀ = P₁
(1450kg)*V = (1450kg + 670kg)*10.6m/s
(1459kg)*V = 22,472 kg*m/s
V = (22,472 kg*m/s)/(1459kg) = 15.4 m/s
So the initial velocity of the torpedo was 15.4 m/s
If you want to learn more about momentum, you can read:
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