Question

how many grams are in 1.62 moles Fe2(SO3)3

Answer 1

Answer:

570. g Fe₂(SO₃)₃

General Formulas and Concepts:
Atomic Structure

• Reading a Periodic Table
• Compounds

Stoichiometry

• Using Dimensional Analysis
• Molar Ratio

Explanation:

Step 1: Define

1.62 moles Fe₂(SO₃)₃

Step 2: Identify

Molar Mass of Fe: 55.85 g/mol

Molar Mass of S: 32.07 g/mol

Molar Mass of O: 16.00 g/mol

Molar Mass of Fe₂(SO₃)₃: 2(55.85) + 3(32.07) + 9(16.00) = 351.91 g/mol

Step 3: Convert

Use dimensional analysis.

1. Set up:                                                                                                              $\displaystyle 1.62 \ \text{moles} \ Fe_2(SO_3)_3 \bigg( \frac{351.91 \ g \ Fe_2(SO_3)_3}{1 \ \text{mole} \ Fe_2(SO_3)_3} \bigg)$
2. Evaluate [Cancel out units]:                                                                        570.094 g Fe₂(SO₃)₃
3. [Round] Significant Figures:                                                                        570.094 g Fe₂(SO₃)₃ ≈ 570. g Fe₂(SO₃)₃

Topic: Chemistry

Unit: Atomic Structure/Stoichiometry