Question

The absolute maximum value of f(x) = x 3 − 3x 2 12 on the closed interval [−2, 4] occurs at what value(s) of x?.

Answer 1

The Answer is 4

3x^2 - 6x

3x(x-2)

x=0 , x=2

f(-2) = -8

f(0) =12

f(4)=