Question

A study was conducted comparing the speeds of 2 different fish, Fish A and Fish B. The table shows the distance, in meters, Fish A travels in seconds. Scientists conclude that Fish B travels 3 meters every 2 seconds. Assuming both fish swim at a constant rate, which fish swims faster and by how many meters per second?

Answer 1

Fish A is faster than fish B by 0.1 m/s

Linear equation

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the y intercept (initial value of y).

Let y represent the distance travelled by the fish after x seconds.

Fish B travels 3 meters every 2 seconds. That is 1.5 m/s

From the table of fish A using the point (0, 0) and (1, 1.6), hence:

Unit rate (m) = (1.6 - 0)/(1 - 0) = 1.6 m/s

Therefore Fish A is faster than fish B by 0.1 m/s (1.6 - 1.5)

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