The activity of the sample when it was shipped from the manufacturer is 4.54 mCi
From the question given above, the following data were obtained:
n = t / t½
n = 48 / 342.72
n = 0.14
N = N₀ / 2ⁿ
N = 5 / 2^0.14
N = 4.54 mCi
Thus, the activity of the sample during shipping is 4.54 mCi
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