Question

A resonant circuit has a peak output voltage of 4.5 mV. What is the voltage at the upper and lower cutoff frequency

Answer 1

Answer:

  3.2 mV

Explanation:

The cutoff frequency is the frequency at which the circuit power output is half the peak value. That means the voltage is (√2/2) times the peak voltage:

  (√2/2)(4.5 mV) ≈ 3.2 mV