This problem is providing us with the mass of bromine gas as 64.065 g so the volume it occupies at STP is required. After the calculations, the result turns out to be 8.96 L.
Ideal gas law:
In chemistry, we use gas laws in order to comprehend the volume-temperature-mole-pressure behavior of gases. In this case, we refer to the ideal gas law as all of the aforementioned variables are taken into account:
[tex]PV=nRT[/tex]
Thus, since STP stand for standard pressure and temperature, 1 atm and 273 K respectively, one must first calculate the moles of bromine gas to subsequently get the volume as follows:
[tex]n=64.064g*\frac{1mol}{159.8g} =0.40mol\\\\V=\frac{nRT}{P} \\\\V=\frac{0.40mol*0.08206\frac{atm*L}{mol*K}*273K}{1atm}\\ \\V=8.96L[/tex]
Learn more about ideal gases: brainly.com/question/4147359
