Water (H2O) forms when hydrogen gas (H2) and oxygen gas (O2) react according to the equation below: 2H2 O2 → 2H2O What mass of water forms when 1. 45 × 10-3 g O2 react completely? (Molar mass of O2 = 32. 00 g/mol; molar mass of H2O = 18. 02 g/mol) 1. 63 × 10-3 g 8. 16 × 10-4 g 1. 29 × 10-3 g.

Respuesta :

The mass of water formed in the reaction is [tex]\rm 1.63\;\times\;10^-^3[/tex] g. Thus, option A is correct.

The balanced chemical equation for the formation of water is:

[tex]\rm 2\;H_2\;+\;O_2\;\rightarrow\;2\;H_2O[/tex]

From the balanced chemical equation, 1 mole of oxygen forms 2 moles of water.

Computation for the mass of water

The moles of a compound is given by:

[tex]\rm Moles=\dfrac{Mass}{Molar\;mass}[/tex]

The moles of oxygen reacted in the reaction are:

[tex]\rm Moles\;O_2=\dfrac{1.45\;\times\;10^-^3\;g}{32\;g/mol} \\Moles\;O_2=0.045\;\times\;10^-^3\;mol[/tex]

The moles of water formed is:

[tex]\rm 1\;mol\;O_2=2\;mol\;H_2O\\0.045\;\times\;10^-^3\;mol\;O_2=0.045\;\times\;10^-^3\;\times\;2\;mol\;H_2O\\0.045\;\times\;10^-^3\;mol\;O_2=0.09\;\times\;10^-^3\;mol\;H_2O[/tex]

The moles of water formed are [tex]\rm 0.09\;\times\;10^-^3[/tex] mol.

The mass of water is given as:

[tex]\rm Mass=Moles\;\times\;Molar\;mass\\Mass\;H_2O=0.09\;\times\;10^-^3\;\times\;18\;g\\Mass\;H_2O=1.63\;\times\;10^-^3\;g[/tex]

The mass of water formed in the reaction is [tex]\rm 1.63\;\times\;10^-^3[/tex] g. Thus, option A is correct.

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