The energy in the capacitor is [tex]2.18*10^-7 J[/tex]
Data;
To solve this question, we have to find the capacitance of the capacitor.
[tex]C = \frac{A \epsilon}{d}\\ A = \pi r^2\\C = (\pi r^2 \epsilon) /d\\[/tex]
Substitute the values into the equation and solve
[tex]C = \frac{\pi r^2 \epsilon}{d}\\C = \frac{3.14 * 0.033^2*8.85*10^-^1^2}{0.001}\\ C = 3.02*10^-^1^1F[/tex]
The energy stored in the capacitor is calculated as
[tex]E = \frac{1}{2}CV^2\\ E= \frac{1}{2}*3.02*10^-^1^1 170^2\\ E = 4.37*10^-^7J[/tex]
The energy stored in the capacitor is 4.37*10^-7 J
since the capacitor will be halved when the separation is doubled and the energy will also be halved.
[tex]W = \frac{4.37*10^-^7}{2} = 2.18*10^-^7J[/tex]
The energy in the capacitor is 2.18*10^-7 J
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