Question

A 0.172 mole sample of solid NaX is dissolved in 275 mL of water in an insulated container at 23.7°C After the solid dissolves, the temperature of the water is 19.2°C. What is the heat of solution of NaX?

Answer 1

The heat of the solution is 29.9kJ

Data given;

• volume = 275mL
• Temperature of the container = 23.7 oC
• Temperature of water = 19.2 oC
• number of moles = 0.172 moles
• specific heat capacity of water = 4.186 g/oC

Mass of Water

Let's calculate the mass of water.

$density = \frac{mass}{volume}\\mass = volume * density\\mass = 275 * 1\\mass = 275g$

Heat Released

The heat released can be calculated using the formula

$Q = mc \delta T\\Q = 275 * 4.186 * (23.7 - 19.2)\\Q = 5180.175J$

The heat released is 5180.175J.

Heat of Solution

The heat of solution is given as

$H = Q/n\\H = 51810.175/0.172\\H = 29943 J/mol\\H = 29.9 kJ/mol$

The heat of the solution is 29.9kJ/mol

Learn more on heat of solution here;

https://brainly.com/question/13439286