Answer:
t ≤ [tex]-\frac{54}{13}[/tex]
Step-by-step explanation:
[tex]\frac{5}{6}[/tex]t−3−3t≥3t+6−3t
[tex]-\frac{13}{6}[/tex]t−3≥6
-[tex]\frac{13}{6}t[/tex]−3+3≥6+3
[tex]\frac{13}{6}[/tex]t≥9
[tex]-\frac{6}{13}[/tex]([tex]-\frac{13}{6}[/tex]t) ≥ [tex]-\frac{6}{13}[/tex](9)
t ≤ [tex]-\frac{54}{13}[/tex]
