Given
in ∆ABC
AB = 5cm
BC = 6 cm
AC = 7 cm
now,
as we have to make ∆PQR inside it
than, possibly ∆PQR's sides length is,
PQ = ½ of CB (according to mid point theorem)
→ CB = 6cm → 6/2 → 3cm
PQ = 3cm
QR = ½ of AC
→ AC/2 = 7/2 = 3.5 cm
RP = ½ of AB
→ AB/2 = 5/2 = 2.5cm
therefore, length of
PQ = 3cm
QR = 3.5 cm
PR = 2.5 cm
Hope this answer helps you dear!
