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Step-by-step explanation:

b. It is a right angle triangle with 2 sides given we are to use Pythagoras theorem.

[tex] {65}^{2} = {25 }^{2} + {x}^{2} [/tex]

[tex]4225 = 625 + {x}^{2} \\{x}^{2} = 4225 - 625 \\ {x}^{2} = 3600 \\ x = 60[/tex]

c. Here 2 angles and one side is given. So we use sine rule

[tex]sin(90) \div 50 = \sin(60) \div x \\ x \sin(90) = 50 \sin(60) \\ x = 25 \sqrt{3} \\ x = 43.3[/tex]

Note: sin 90 is 1

sin 60 is √3 /2

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a. since the x is the same we would use sin rule

[tex] \sin(45) \div x = \sin(90) \div 16 \\ x = 16 \sin(45) \\ x = 16 \times \sqrt{2} \div 2 \\ x = 8 \sqrt{2} [/tex]

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