emilianosevilla2727 emilianosevilla2727

21-01-2022
Chemistry

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nuralfaqih nuralfaqih

21-01-2022

Known :

P1 = 0.328 atm

V1 = 254.9 mL

P2 = 0.679 atm

Solution :

Isothermic Process

P1 • V1 = P2 • V2

0.328 • 254.9 = 0.679 • V2

V2 = 123.1 mL

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