Question

A sample of steel is added to a 100-mL graduated cylinder with 45.0 mL of water. Ifthe resulting water level is 55.5 mL, what is the volume of the steel

Answer 1

This problem is providing the total volume of a graduated cylinder, 100 mL with 45.0 mL of water, but when adding a piece of steel, the volume rises to 55.5 mL so the volume of the metal is required and found to be 10.5 mL according to:

Displaced volume:

In chemistry, density experiments require the use of a well-measured volume of water in order to add the density-unknown object so the difference in the volume lead to the that of the object.

In such a way, since 45.0 mL of water is risen to 55.5 mL upon the addition of the steel, one can calculate the difference in order to get the volume of steel as 55.5 mL comprises both water and the object:

$V^{steel}=55.5mL-45.0 mL\\\\V^{steel}=10.5 mL$

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