Question

What is the solution of StartRoot x + 12 EndRoot = x?

Answer 1

Answer:

$x = 4 \\ or\\ x=-3$

Step-by-step explanation:

$x² - x - 12 = 0 x² - 4x + 3x - 3*4 =0 x*(x - 4) + 3*(x - 4)= 0 (x- 4 )(x+3) =0 x -4 =0 or x + 3 = 0 x = 4 or x = -3$

Ignore the  grammatical error

Answer 2

Answer:

c

Step-by-step explanation: