Given the volume of a triangular pyramid as v = 1 / 2 bhl, the volume is v = 3 / 2 h⁶
where
b = base
h = height
l = length
Therefore,
b = 3h
l = h⁴
Therefore,
v = 1 / 2 × 3h × h × h⁴
v = 3h⁶ / 2
Therefore,
v = 3 / 2 h⁶
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