The probability would be 1/4
The cross is a dihybrid one between high bone density, no adermatoglphia individual (Hhaa) and no high bone density, adermatoglyphia individual hhAa.
Based on the assumption that H is dominant over h and A is dominant over a.
Hhaa x hhAa (see the attached image for the Puneet's square result)
Offspring:
More on dihybrid crosses can be found here: https://brainly.com/question/1185199?referrer=searchResults