How do I solve this?
3(√x+1-5)=27
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3(√x+1-5)=27
divide both sides by 3
√x+1-5= 27
add 5 to both sides
√x+1=27+5
√x+1=32
take square of both sides
x+1=32
subtract 1 from each sides
x=32-1
x=31