A charged particle is located in an electric field where the magnitude of the electric field strength is 2.0x10^3 newtons per coulomb. If the magnitude of the electrostatic force exerted on the particle is 3.0x10^-3 newton, what is the charge of the particle?

Respuesta :

Answer:

20.7

Explanation:

:0 because basis  of the daily occured

The charge of the particle located in an electric field where the field strength is 2×10³ N/C is 1.5×10¯⁶ C

What is electric field strength?

This is simply defined as the force per unit charge. Mathematically, it is expressed as:

E = F / Q

Where

E is the electric field strength

F is the force

Q is the charge

How to determine the charge

From the question given above, the following data were obtaine:

  • Electric field strength (E) = 2×10³ N
  • Force (F) = 3×10¯³ N
  • Charge (Q) =?

E = F/Q

2×10³ = 3×10¯³ / Q

Cross multiply

2×10³ × Q = 3×10¯³

Divide both side by 2×10³

Q = 3×10¯³ / 2×10³

Q = 1.5×10¯⁶ C

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