Question

How to solve exponential equations with constant prime numbers or number whos fractors are primes?
Example: 3^x+2+3^x−3=244

Answer 1

Answer:

$x=3$

Step-by-step explanation:

$3^{x+2}+3^{x-3}=244$

$3^x3^2+\frac{3^x}{3^3} =244$

$3^x(9+\frac{1}{27})=244$

$3^x(\frac{244}{27})=244$

$3^x=27$

$x=log_3(27)$

$x=3$