Respuesta :

Answer:

[tex]y=-\frac{1}{4}x-\frac{5}{2}[/tex]

Step-by-step explanation:

Point-Slope Form: [tex](y-y_{0})=m(x-x_{0}) [/tex] where [tex](x_{0},y_{0}) [/tex] is the point our line is passing through and [tex]m[/tex] is the slope of our line.

The question asks us for an equation parallel to [tex]y=-\frac{1}{4}x+5 [/tex].

We identify that the equation provided is in y-intercept form: [tex]y=mx+b[/tex]

A line parallel to [tex]y=-\frac{1}{4}x+5 [/tex] will have the same slope.

Thus, [tex]m=-\frac{1}{4} [/tex].

We were provided the point [tex](2,-3)[/tex].

Plugging into our equation for point-slope form:

[tex](y+3)=-\frac{1}{4} (x-2) [/tex]

This is our answer, however we can simplify this equation into y-intercept form by simply solving for y:

[tex]y=-\frac{1}{4}x+\frac{2}{4}-3 [/tex]

[tex]y=-\frac{1}{4}x+\frac{1}{2}-\frac{6}{2} [/tex]

[tex]y=-\frac{1}{4}x-\frac{5}{2}[/tex]

Thus, the equation parallel to [tex]y=-\frac{1}{4}x+5 [/tex] passing through [tex](2,-3)[/tex] is:

[tex]y=-\frac{1}{4}x-\frac{5}{2}[/tex]