32. Select the equation that is correctly displayed in point-slope form:
![32 Select the equation that is correctly displayed in pointslope form class=](https://us-static.z-dn.net/files/db2/d0ab73ec068ee2b999a7a44674f45e4b.png)
Answer:
[tex]y=-\frac{1}{4}x-\frac{5}{2}[/tex]
Step-by-step explanation:
Point-Slope Form: [tex](y-y_{0})=m(x-x_{0}) [/tex] where [tex](x_{0},y_{0}) [/tex] is the point our line is passing through and [tex]m[/tex] is the slope of our line.
The question asks us for an equation parallel to [tex]y=-\frac{1}{4}x+5 [/tex].
We identify that the equation provided is in y-intercept form: [tex]y=mx+b[/tex]
A line parallel to [tex]y=-\frac{1}{4}x+5 [/tex] will have the same slope.
Thus, [tex]m=-\frac{1}{4} [/tex].
We were provided the point [tex](2,-3)[/tex].
Plugging into our equation for point-slope form:
[tex](y+3)=-\frac{1}{4} (x-2) [/tex]
This is our answer, however we can simplify this equation into y-intercept form by simply solving for y:
[tex]y=-\frac{1}{4}x+\frac{2}{4}-3 [/tex]
[tex]y=-\frac{1}{4}x+\frac{1}{2}-\frac{6}{2} [/tex]
[tex]y=-\frac{1}{4}x-\frac{5}{2}[/tex]
Thus, the equation parallel to [tex]y=-\frac{1}{4}x+5 [/tex] passing through [tex](2,-3)[/tex] is:
[tex]y=-\frac{1}{4}x-\frac{5}{2}[/tex]