Question

what’s the inverse function of

h(x)=2/x+1 ?

Answer 1

Answer:

h(x)=log2(x)

Step-by-step explanation:

The find the inverse of an invertible function y=f(x),

swap y and x and solve for y.

 We have h(x)=y=2x.

Swapping x and y gives x=2y.
                                We now wish to solve for y.Take the log with base 2 of both sides of the equation to free the y variable.

x=2ylog2(x)=log2(2y)=yThus, y=h(x)=log2(x).
See that we used the fact that logn(nx)=x

Answer 2

Answer:

If I understand correctly, your trying to find the inverse function of:

h(x)= $\frac{2}{x}$ + 1, If so...

Answer: