A source charge of 5. 0 µC generates an electric field of 3. 93 × 105 at the location of a test charge. How far is the test charge from the source charge? 0. 11 m 0. 34 m 1. 1 m 3. 4 m.

Respuesta :

The distance of the test charge from the source charge is 1.1 m. Option A is correct.

What does Gauss Law state?

It states that the electric flux across any closed surface is directly proportional to the net electric charge enclosed by the surface.[tex]R= \sqrt \dfrac {Qk^}E[/tex]

Where,

[tex]E[/tex] = electric force = 3. 93 × 10⁵  N/C

[tex]k[/tex] = Coulomb constant = [tex]8.99 \times 10^9 \rm\ N m ^2 /C ^2[/tex]

[tex]Q\\ [/tex]     = charges =  5.0 µC

[tex]r[/tex] = distance of separation =?

Put the values in the formula,

[tex]R= \sqrt \dfrac {5\times 10^{-6}8.99 \times 10^9}{3. 93 \times 10^5}}\\\\ R = 1.1 \rm \ m[/tex]

Therefore, the distance of the test charge from the source charge is 1.1 m.

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