The distance of the test charge from the source charge is 1.1 m. Option A is correct.
It states that the electric flux across any closed surface is directly proportional to the net electric charge enclosed by the surface.[tex]R= \sqrt \dfrac {Qk^}E[/tex]
Where,
[tex]E[/tex] = electric force = 3. 93 × 10⁵ N/C
[tex]k[/tex] = Coulomb constant = [tex]8.99 \times 10^9 \rm\ N m ^2 /C ^2[/tex]
[tex]Q\\ [/tex] = charges = 5.0 µC
[tex]r[/tex] = distance of separation =?
Put the values in the formula,
[tex]R= \sqrt \dfrac {5\times 10^{-6}8.99 \times 10^9}{3. 93 \times 10^5}}\\\\ R = 1.1 \rm \ m[/tex]
Therefore, the distance of the test charge from the source charge is 1.1 m.
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