(07.02 MC)
Please help me with this math

Answer:
∠ P ≈ 35.9°
Step-by-step explanation:
Using the sine ratio in the right triangle
sinP = [tex]\frac{opposite}{hypotenuse} [/tex] = [tex]\frac{QR}{PR} [/tex] = [tex]\frac{33.8}{57.6} [/tex] , then
∠ P = [tex]sin^{-1} [/tex] ( [tex]\frac{33.8}{57.6} [/tex] ) ≈ 35.9°