Question

A hydraulic lift is used to lift a car. The small piston has an area of 5 cm2 and the large piston has an area of 50 cm2. If a driver applies a force of 30 N to the small piston, what is the weight of the car the large piston can support

Answer 1

The weight of the car the large piston can support is 300 N.

What is weight?

Weight can be defined as the gravitational pull on an object. Or it can be defined as the product of mass and gravity of an object.

To calculate the weight of the car the large piston can support, we use the formula below.

Formula:

• f/a = F/A.................. Equation 1

Where:

• F = Weight of the car the large piston can support.
• A = Area of the large piston
• f = Force applied to the small piston
• a = Area of the small piston

Make F the subject of the equation.

• F = fA/a.................. Equation 2

From the question,

Given:

• f = 30 N
• A = 50 cm²
• a = 5 cm².

Substitute these values into equation 2

• F = 30(50)/5
• F = 300 N.

Hence, the weight of the car the large piston can support is 300 N.

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