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Line g passes through points (1, 1) and (10, 9). Line h is perpendicular to g. What is the
slope of line h?

Respuesta :

Answer:

[tex]\bold{The~slope~of~line~h~is~-\frac{9}{8}. }[/tex]

Step-by-step explanation:

Hi there!

First, let's calculate the slope of line g.

[tex]\displaystyle\frac{y2-y1}{x2-x1} [/tex]

[tex]\displaystyle\frac{9-1}{10-1} \\ \displaystyle\frac{8}{9} [/tex]

So, the slope of line g is [tex]\displaystyle\frac{8}{9} [/tex]

Now let's identify the slope of line h.

We are given that line h is perpendicular to line g.

Now, perpendicular lines have slopes that are opposite reciprocals.

This means we take a number, flop it over, and change its sign.

The slope of line g is

[tex]\displaystyle\frac{8}{9} [/tex]

Now, we flop it over:

[tex]\displaystyle\frac{9}{8} [/tex]

Then, we change its sign:

[tex]\displaystyle-\frac{9}{8} [/tex]

Thus, [tex]\displaystyle-\frac{9}{8} [/tex] is our final answer.

Hope it helps! Enjoy your day! (:

[tex]\bold{GazingAtTheStars}[/tex]

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