Question

Use the given frequency distribution to find the
(a) class width
(b) class midpoints
(c) class boundaries

Temperature (°F):
40-42
43-45
46 48
49 51
52-54
55 57
58-60

Frequency
1
3
5
11
7
7
1


(a) What is the class width?

( Type an integer or a decimal)

Answer 1

The class width is 2, and the class midpoint of the first class is 41

What are classes?

Classes are the intervals of data elements in a range

(a) The class width

This is the difference between the class intervals.

Using the first class, we have:

$Width =42 - 40$

$Width = 2$

Hence, the class width is 2

(b) The class midpoints

This is the mean of the class intervals.

So, the class midpoints are: 41, 44, 47, 50, 53, 56 and 59

(c) The class boundary

This is the mean of a lower class interval, and the next upper class interval.

So, the class boundaries are:

39.5 - 42.5, 42.5 - 45.5, 45.5 - 48.5, 48.5 - 51.5, 51.5 - 54.5, 54.5 - 57.5, 57.5 - 60.5

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