Given equation is {(3x+1)/5} = {(2x-2)/6}
On applying cross multiplication then
⇛6(3x+1) = 5(2x-2)
Multiply the numbers outside the bracket with numbers in bracket.
⇛18x + 6 = 10x - 10
Shift the variable value on LHS and the constant value on RHS.
⇛18x - 10x = -6-10
Subtract the values on LHS and RHS.
⇛8x = -16
Shift the value 8 from LHS to RHS.
⇛x = -16÷8 = -16/8
⇛x = -2
Therefore, x = -2
Answer: Hence, the value of x for the given problem is -2
Please let me know if you have any other questions.
