2 seconds into its acceleration, the jet was moving at 430 km/hr
Linear motion
From the question,
We are to determine how fast the jet was going 2 seconds into its acceleration.
From one of the equations of kinematics for linear motion, we have
v = u +at
Where
v is the final velocity
u is the initial velocity
a is the acceleration
and t is the time
Now, we will determine the velocity, v, at time 2 seconds.
From the given information
u = 400 km/hr
a = 15 km/hr/s
and t = 2 secs
Putting the parameters into the formula, we get
v = 400 + (15 × 2)
v = 400 + 30
v = 430 km/hr
Hence, 2 seconds into its acceleration, the jet was moving at 430 km/hr
Learn more on linear motion here: https://brainly.com/question/19365526
