Question

Solve for d. TYPE ONLY THE NUMERIC ANSWER

2d+2=4

Question 11 options:

Answer 1

Answer:

your answer is 2

Step-by-step explanation:

2d+2=4

Subtract 2 from both sides

2d=4

then divide both sides by 2 to get the d by itself

d=2

so your answer is 2

Answer 2

Answer:

$\boxed{\tt \: d = 1}$

Step-by-step explanation:

$\bf \: Given \: equation :$

$2d + 2 = 4$

We need to find the value of d.

$\bf \: Solution:$

$\sf \implies2d+2=4$

Step 1 : $\rm Subtract\; 2\: from\; both\; sides :$

$\sf \implies \: 2d + 2 - 2 = 4 - 2$

• Simplify this :

$\sf \implies2d + 0 = 2$

$\sf \implies2d = 2$

Step 2 : $\rm Divide \; each \: sides \; by \; 2 :$

$\sf \implies \cfrac{2d}{2} = \cfrac{2}{2}$

$\rm \: Cancel \: the \: LHS :$

• Cancel 2 (which is on the numerator) and cancel 2 (which is on the denominator) by 2 :- [Leave d]

$\sf \implies \cfrac{ \cancel2d}{ \cancel2} = \cfrac{2}{2}$

• Results to,

$\sf \implies \cfrac{ {}^{1} \cancel2d}{ {}^{1} \cancel2} = \cfrac{2}{2}$

$\sf \implies 1d = \cfrac{2}{2}$

We know that 1d = d. So,

$\sf \implies \: d = \cfrac{2}{2}$

$\rm \: Now \:Cancel \: the \: RHS :$

• Cancel 2 (which is on the numerator) and cancel 2(which is on the denominator) by 2 :

$\sf \implies{d} = \cfrac{ \cancel2}{ \cancel2}$

• Results to,

$\sf \implies{d} = \cfrac{ \cancel2 {}^{1} }{ \cancel2{}^{1} }$

$\sf \implies{d} = 1$

Hence, the value of d would be 1.

$\rule{225pt}{2pt}$

I hope this helps!

Let me know if you have any questions.