A cell phone is at rest on a tabletop and the phone’s owner flicks the phone with their fingers, which applies a 0.01 N force to the phone. The phone is accelerated at a rate of 0.1 m/s^2 in the direction of the flick. What is the mass of the phone?​

Respuesta :

The mass of the cell phone flicked by the owner is 0.1 kilogram.

Given the data in the question;

  • Force applied to the phone; [tex]F = 0.01N = 0.01kgm/s^2[/tex]
  • Acceleration of the phone; [tex]a = 0.1m/s^2[/tex]

Mass of the phone; [tex]m = \ ?[/tex]

Force

Force is simply referred to as the strength exerted that can change the motion of a particle or object. It can either be a pull or a push. It can be expressed as;

[tex]F = m * a[/tex]

Where m is mass of the object and a is its acceleration.

To determine the mass of the phone, we input our given values into the expression above.

[tex]F = m * a\\\\0.01kgm/s^2 = m * 0.1m/s^2\\\\m = \frac{0.01kgm/s^2}{0.1m/s^2} \\\\m = 0.1kg\\[/tex]

Therefore, the mass of the cell phone flicked by the owner is 0.1 kilogram.

Learn more about force: https://brainly.com/question/19852583

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