The relation of uniform motion allows to find the result for the speed of the Ship is;
Kinematics studies the movement of bodies, looking for relationships between position, velocity and acceleration, in the special case that acceleration is zero, it is called uniform motion.
[tex]v= \frac{\Delta x}{t}[/tex]
where v is the speed, dx is the displacement, and t is the time.
They indicate that the average speed of the transatlantic was v= 65.5 km/h and a time of 3 days, 10 hours and 40 minutes was used.
The unit systems are measurement systems that establish conventional to share measurements with precision and without errors, the most used is the International System of Measurements (SI), where the basic measurements are the meter and the second, let's reduce the magnitudes to these units .
v= 65.5km/h ( [tex]\frac{1000 m}{1 km}[/tex] ) ( [tex]\frac{1 h}{3600 s}[/tex] ) = 18.19m/s
t = t₁ +t₂ +t₃
t₁= 3 days (24h/1day) (3600s/1h) = 259200s
t₂ = 10h ( 3600s/1h) = 36000s
t₃ = 40min ( 60s/1min) = 2400s
t = 259,200 + 36,000 + 2,400 = 297,600 s
Let's find the distance traveled.
Δx = vt
Δx = 18.19 297600
Δx = 5.41 10⁶ m
This distance is the same for both ships, they indicate that the time of the Queen Mary Ship is 10h 2 min more than the ocean liner.
Δt = 10h (3600/1h)+ 2min (60s/1min) = 36120s
The total time of the Queen Mary is
[tex]t_{Queen} = t_{transatlantic} + \Delta t[/tex]
[tex]t_{Queen}[/tex] = 297600 + 36120
t_{Queen} = 333720 s
We look for the average speed of the Queen MMary
v= [tex]\frac{ \Delta x}{t}[/tex]
v = [tex]\frac{5.41 \ 10^6 }{333720}[/tex]
v = 16.22m/s
In conclusion using the uniform motion relation we can find the result for the speed of the ship is;
Learn more about average speed here: brainly.com/question/25638908
