Question

A 0.366 g sample of hydrated tin(II) chloride (SnCl2•xH2O) is found to contain 0.0586 g of water. What is the approximate percent of water in the hydrate? What is the value of x?
16%

2. 81%

3. 84%

4. 75%

5. 19%
Part 2
1. 5

2. 1

3. 4

4. 2

5. 6

6. 3

Answer 1

1. The approximate percent of water in the hydrate is 16%

2. The value of x in the hydrate is 2

Data obtained from the question

• Mass of hydrate, SnCl₂•xH₂O = 0.366 g

• Mass of water, H₂O = 0.0586 g

• Percentage of water =?

• Value of x =?

1. How to determine the percentage of water in the hydrate

Mass of hydrate, SnCl₂•xH₂O = 0.366 g

Mass of water, H₂O = 0.0586 g

Percentage of water =?

Percentage = (mass of water / mass of hydrate) ×100

Percentage of water = (0.0586 / 0.366) × 100

Percentage of water = 16%

2. How to determine the value of x

To obtain the value of x, we shall determine the formula of the hydrate. This can be obtained as follow:

• Mass of hydrate, SnCl₂•xH₂O = 0.366 g

• Mass of water, H₂O = 0.0586 g

• Mass of anhydrous, SnCl₂ = 0.366 – 0.0586 = 0.3074

• Formula of hydrate =?

Divide by their molar mass

SnCl₂ = 0.3074 / 190 = 0.0016

H₂O = 0.0586 / 18 = 0.0032

Divide by the smallest

SnCl₂ = 0.0016 / 0.0016 = 1

H₂O = 0.0032 / 0.0016 = 2

Thus, the formula of the hydrate is SnCl₂•2H₂O

Comparing the formula of the hydrate (SnCl₂•2H₂O) with SnCl₂•xH₂O, we can see that the value of x is 2

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