Question

An object accelerates from rest to 105 m/s over a distance of 51 m. What
acceleration did it experience?

Answer 1

The object's acceleration is $108.1 ms^{-2$

What is acceleration?

Acceleration is the rate of change of velocity over time

The given parameters are:

• Initial velocity: u = 0 m/s
• Final velocity: v = 105 m/s
• Distance: s = 51 m

The acceleration (a) is then calculated using:

$v^2 = u^2 + 2as$

So, we have:

$105^2 = 0^2 + 2 \times a \times 51$

Simplify

$11025 = 102a$

Make a the subject

$a= 108.1$

Hence, the object's acceleration is $108.1 ms^{-2$

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