Question

If x is the average (arithmetic mean) of m and 9, y is the average of 2m and 15, and z is the average of 3m and 18, what is the average of x, y, and z in terms of m?

Answer 1

The average of x, y, and z in terms of m is; 3m + 21

Average Mean

We are told that;

x is the average (arithmetic mean) of m and 9. Thus;

x = (m + 9)/2

y is the average of 2m and 15 and so;

y = (2m + 15)/2

z is the average of 3m and 18 and so;

z = (3m + 18)/2

Thus, average of x, y and z is;

¹/₂(m + 9) + ¹/₂(2m + 15) + ¹/₂(3m + 18)

⇒ ¹/₂(m + 9 + 2m + 15 + 3m + 18)

⇒ ¹/₂(6m + 42)

⇒ 3m + 21

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