Answer:
Explanation:
Mass of 1 mol of C2H6
2*C = 2*6 = 12
6 H = 6*2 = 6
1 mol = 18 grams
Mols of C2H6 when 30 grams of Ethane is used.
mols = given mass / molar mass
given mass = 30 grams
molar mass = 18 grams
mols = 30 / 18
mols = 1.6666667 moles
Mols of CO2
2 ethane 2.66667
======= = ==========
4 CO2 x
Cross multiply
2x = 2.66667 * 4
2x = 10.66668 Divide by 2
x = 5.333334 Moles CO2
Molar Mass CO2
C = 12
2*O2 = 16
1 mol CO2 = 28
Grams CO2
Grams CO2 = mols * 28
Grams CO2 = 5.3334 * 28
Grams CO2 = 149.333
