Question

A skydiver who has a mass of 50.0 kilograms opens a parachute. The air resistance of the parachute provides an upward force of 340 N. With the parachute open, how fast does the skydiver accelerate while continuing to fall

Answer 1

The acceleration of the skydiver while falling is 3 m/s².

What is acceleration?

This can be defined as the rate of change of velocity. The S.I unit of acceleration is m/s².

To calculate the acceleration of the parachute, we use the formula below.

Formula:

• mg-F = ma............. Equation 1

Where:

• m = mass of the skydiver

• F = upward force
• g = acceleration due to gravity
• a = acceleration of the skydiver.

 make a the subject of the equation

• a = (mg-F)/m............... Equation 2

From the question,

Given:

• m = 50 kg
• F = 340 N
• g = 9.8 m/s²

Substitute these  values into equation 2

• a = [(50×9.8)-340]/50
• a = 150/50
• a = 3 m/s²

Hence, the acceleration of the skydiver while falling is 3 m/s²

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