Answer:
CH4
Explanation:
I'll assume the x is the subscript for the hydrogen, as in CH[tex]x[/tex]
We have 9g of C in the 12 gram sample. The remainder is hydrogen, H, we're promised. That means 3 grams of H.
Let's convert these two masses into moles of C and H. With moles, we are able to see the count relationship between the two elements.
Moles C = 9 g/12 g/mole = 0.70 moles C
Moles H = 3g/1 g/mole = 3.0 moles H
See the attached table.
We want whole numbers so let's take (1/0.70) = 1.33455 and then multiply this factor by both mole values:
Moles C = 1
Moles H = 4.0037, which we'll round to 4
There are 4 H for every 1 C
CH[tex]4[/tex]