Respuesta :

Step-by-step explanation:

  • [tex] \sf \: 4 {x}^{2} + 31x + 21[/tex]

  • [tex] \sf \: 4 {x}^{2 + } 28x + 3x + 21[/tex]

  • [tex] \sf \: 4x(x + 7) \: 3(x + 7)[/tex]

  • [tex] \sf \: (4x + 3)(x + 7)[/tex]

Hope It's Helps^^

When the expression 4x² + 31x + 21 is factorised, the result obtained is (4x + 3)(x + 7)

Data obtained from the question

  • 4x² + 31x + 21
  • Factorisation =?

How to factorise

4x² + 31x + 21

  • Multiply the 1st term (i.e 4x²) and the last term (i.e 21) together.
  • The result is 84x².
  • Find the two factors of 84x² such that the sum of the factors is equal to 31x
  • The factors are 28x and 3x
  • Substitute 28x and 3x in place of 31x in the equation above. We have

4x² + 31x + 21

4x² + 28x + 3x + 21

Factorise

4x(x + 7) + 3(x + 7)

(4x + 3)(x + 7)

Learn more about factorisation:

https://brainly.com/question/22248251