Respuesta :
Step-by-step explanation:
- [tex] \sf \: 4 {x}^{2} + 31x + 21[/tex]
- [tex] \sf \: 4 {x}^{2 + } 28x + 3x + 21[/tex]
- [tex] \sf \: 4x(x + 7) \: 3(x + 7)[/tex]
- [tex] \sf \: (4x + 3)(x + 7)[/tex]
Hope It's Helps^^
When the expression 4x² + 31x + 21 is factorised, the result obtained is (4x + 3)(x + 7)
Data obtained from the question
- 4x² + 31x + 21
- Factorisation =?
How to factorise
4x² + 31x + 21
- Multiply the 1st term (i.e 4x²) and the last term (i.e 21) together.
- The result is 84x².
- Find the two factors of 84x² such that the sum of the factors is equal to 31x
- The factors are 28x and 3x
- Substitute 28x and 3x in place of 31x in the equation above. We have
4x² + 31x + 21
4x² + 28x + 3x + 21
Factorise
4x(x + 7) + 3(x + 7)
(4x + 3)(x + 7)
Learn more about factorisation:
https://brainly.com/question/22248251