Using simple interest, it is found that Katelyn's brother borrowed 15,889 for school.
The amount of interest after t years in simple interest is modeled by:
[tex]I(t) = Prt[/tex]
In which:
In this problem:
Then:
[tex]I(t) = Prt[/tex]
[tex]5720 = P(0.06)(6)[/tex]
[tex]0.36P = 5720[/tex]
[tex]P = \frac{5720}{0.36}[/tex]
[tex]P = 15889[/tex]
Katelyn's brother borrowed 15,889 for school.
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